WebAug 9, 2024 · When the role logs into the Snowflake web UI (for instance), they cannot see any of the tables under the "Databases" tab, but they can see the database and they can see the schemas and they can see the INFORMATION_SCHEMA views (I also executed GRANT SELECT ON ALL VIEWS IN DATABASE). Webgrant select on all tables in schema qa_tickit to fred; The following example grants all schema privileges on the schema QA_TICKIT to the user group QA_USERS. Schema privileges are CREATE and USAGE. USAGE grants users access to the objects in the schema, but doesn't grant privileges such as INSERT or SELECT on those objects.
How to grant access to all tables in a schema - TechPaste.Com
WebDec 29, 2024 · Specifies a permission that can be granted on a schema. For a list of the permissions, see the Remarks section later in this topic.. ON SCHEMA :: schema*_name* Specifies the schema on which the permission is being granted. The scope qualifier :: is required. database_principal Specifies the principal to which the permission is being … WebTo grant the privileges, use the Postgres session. Once granted, try to rerun the previous command. That’s it. You managed to grant the select privilege to the specific user. 2. … martin bowling alley
GRANT - CockroachDB
WebSep 16, 2024 · Grant SELECT privilege on all tables for a particular database: use role accountadmin; grant usage on database MY_DB to role TEST_ROLE; grant usage on all schemas in database MY_DB to role TEST_ROLE; grant select on all tables in database MY_DB to role TEST_ROLE; Future Tables : Grant SELECT privilege on all future … WebOption 1: performing the grant select explicitly on each table in the schema…so if you have 300 tables in your schema “HR”…you will execute : GRANT SELECT on HR.XXXX to … WebAs discussed in the question at GRANT SELECT to all tables in postgresql, as of PG 9.0 you can mass-grant privileges on all existing tables to user u, using a command like: GRANT ALL ON ALL TABLES IN SCHEMA public TO u; Logged in as u, you can now do this to pre-existing table a: SELECT * FROM a; But if you now create table b and do: martin boyd fis