Nettet29. mar. 2012 · int a = 10; int b = a++; In that case, a becomes 11 and b is set to 10. That's post-increment - you increment after use. If you change that line above to: int b = ++a; then a still becomes 11 but so does b. That's because it's pre-increment - you increment before use. Note that it's not quite the same thing for C++ classes, there are ...Nettet6. sep. 2024 · The answer is the option (1). Explanation: Here the expression a**b*a + *b uses pointer in C/C++ concept. Here a**b*a + *b means 5* (value of pointer b that is …
c++ - What does the operation c=a+++b mean? - Stack …
Nettet1. Unless you are writing a C++ parser/compiler, you should never have to write/think about expressions like a+++b, which someone reading the code later could easily … churches savage mn
Operators in C++ - GeeksforGeeks
That is, whether the first ++a is evaluated first or the second ++a is evaluated first in either case a is incremented twice and then the + operator takes effect, so the eventual equation is either b = 2 + 3; or b = 3 + 2 thus b = 5. When I get home I will try this on with my C compiler.Nettet8. des. 2024 · @Saurabh P Bhandari, It's not UB. You might be thinking of a++ + a which is UB because it both reads from and writes to a. C uses the longest sequence that forms a token when tokenizing, so a+++b mans a++ + b, which is perfectly ok. –Nettet7. aug. 2024 · 所以,这个语句执行顺序是:. 先做 ++a, 这个时候a的值已经变成了1并且参与运算(就是先赋值,后参与运算). 然后做 a++, a的值变成了2但是不参与运算(就是先参与运算,运算结束后赋值). 然后在运算的时候,两个a参与运算的值都是1,b就是2了. 然 …churches savannah ga